How to Calculate Cement, Sand and Aggregate quantity in 1 cubic meter Concrete

Calculation of Materials for M-20 Grade of Concrete

cement sand aggregate

M-20 = 1 : 1.5 : 3

where

  • M  =  Mix
  • 20 =  Compressive strength of concrete ( 20 N/mm2 )
  • Ratio →  1 part of cement, 1.5 parts of sand, 3 parts of the aggregate

Assume that the calculation of concrete material is for 1 m3 wet volume.

Dry volume = Wet volume  ( 1.54 to 1.57 ) times the wet volume of concrete.

Sum of the ratio for M-20 = 1 + 1.5 + 3 = 5.5

Now change 1 m3 wet volume to dry volume

∴ Dry volume = Wet volume x 1.57  1  x  1.57  =  1.57 m3

 

Volume of Cement

Cement volume = (1/5.5) x 1.57 = 0.285 m3

Volume of cement in kg = 0.2854 x 1440 = 410.9 ≈ 411 kg                                [♦ Density of cement = 1440 kg/m3]

Quantity of cement (bags) = 411/50 = 8.22 ≈ 8 bags.                                        [♦ Weight of 1 bag of cement = 50 kg]

Volume of Sand

Sand volume = (1.5/5.5) x 1.57 = 0.428 m3.

Volume of Aggregate

Aggregate volume = (3/5.5) x 1.57 = 0.856 m3.

 

Therefore, materials required for 1 mof Concrete

  • Cement quantity = 8 bags.
  • Sand quantity = 0.428 m3.
  • Aggregate quantity = 0.856 m3.

 

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